8 psi on a Mitsubishi turbo is different than 8 psi in a gt35. Don’t go by psi. Go by power.
what do i need to turbo my integra
i have most of the things to boost my 99 integra ls i think all i have left is injectors fuel pump and an ecu that is tunable what size injectors and fuel pump do i need tho i’m looking to run about anywhere from 8-12 pounds cuz it’s my daily it’s a stock block no other mods
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^^^This.
Not sure why you're setting a PSI goal. Set a power goal, and your question can be answered. It can't be answered until you do so.
Not sure why you're setting a PSI goal. Set a power goal, and your question can be answered. It can't be answered until you do so.
umm 250-300 does that help?
I'm assuming you want that to be whp, and not crank HP, correct?
Formula for estimating how big of an injector you need:
Horsepower x B.S.F.C (brake specific fuel consumption)
Divided by____
Number of injectors x .80
.80 being maximum duty cycle (think of this as being the max output of the injector - in our scenario here, we're saying we want 80% of the injector's capacity to be the 'max' output. In other words, let's not overwork the injector if we don't have to)
.60 being B.S.F.C. (pounds per hour for a boosted engine)
300whp (wheel-HP) as your goal
Add approx 20% to your goal as you want the formula to be calculated for crank hp, not whp. That comes to approx. 360 crank hp.
Obviously, there are tons of variables when it comes to drivetrain loss. I'm using that just for example purposes.
Your formula should now be:
360 x .60
____ = 67.5 lbs./hr (per injector)
4(# of injectors) x .80
Convert to cc/min= 67.5 x 10.5 = 708.75cc injector needed (minimum)
I'd be looking for an injector in the 750cc-850cc range. Err on the side of higher to allow for additional fueling in the future if your WHP goals change in the future.
Formula for estimating how big of an injector you need:
Horsepower x B.S.F.C (brake specific fuel consumption)
Divided by____
Number of injectors x .80
.80 being maximum duty cycle (think of this as being the max output of the injector - in our scenario here, we're saying we want 80% of the injector's capacity to be the 'max' output. In other words, let's not overwork the injector if we don't have to)
.60 being B.S.F.C. (pounds per hour for a boosted engine)
300whp (wheel-HP) as your goal
Add approx 20% to your goal as you want the formula to be calculated for crank hp, not whp. That comes to approx. 360 crank hp.
Obviously, there are tons of variables when it comes to drivetrain loss. I'm using that just for example purposes.
Your formula should now be:
360 x .60
____ = 67.5 lbs./hr (per injector)
4(# of injectors) x .80
Convert to cc/min= 67.5 x 10.5 = 708.75cc injector needed (minimum)
I'd be looking for an injector in the 750cc-850cc range. Err on the side of higher to allow for additional fueling in the future if your WHP goals change in the future.
okay so 850cc injectors thank you and what fuel pump?
A Walbro 450 should be sufficeokay so 850cc injectors thank you and what fuel pump?
that seems like overkill for 300 hp are there downsides to having injectors and pump thar r bigger than needed?A Walbro 450 should be suffice
No. But - there will be if you don't have enough.that seems like overkill for 300 hp are there downsides to having injectors and pump thar r bigger than needed?
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